The VSEPR model suggests that the bond angles of both H₂O and H₂S are reduced from the ideal 109.5° tetrahedral bond angle. Calculations demonstrate, however, that the angles for both compounds start around 90° as predicted from the bonding diagrams and open up as the second bond forms.

Here is a graph of the H-O-H and H-S-H angles as the second H is brought in:

Note that both angles start around 90° (less than that, in fact) when the second H is 1 Å or more beyond the minimum separation, R_e. The bond angle of H₂S doesn't change much—about 5°— while the bond angle of H₂O is forced open substantially the closer the second H gets to O, until it has increased by more than 15° from where it is at R_e + 1 Å.